If the wave-spring washer is supposed to be slightly deformed with the proper amount of shims, using the method outlined, wouldn't the correct number of shims be n + 1?
It should be the maximum number of shims while the wavy washer still waves. This ensures that the side load on the bearings is only as hard as the wavy washer can push, but leaves almost no room for lateral loads to make the crank slide left-right on the spindle. So it's n, with n being the maximum number of shims you can slip into the space created by the wavy washer.
For clarity, when I say "space", I'm not talking about a circumferential gap, merely the valleys between the waves.
I hope I didn't make it seem more confusing than it is.