On the road today...

Questions about bike hire abroad and everything light bike related. No off-topic chat please

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makoy
Posts: 716
Joined: Sun Sep 05, 2010 11:33 am
Location: Subic Bay, Philippines

by makoy

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subic bay, philippines

by Weenie


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CarpetFibre
Posts: 556
Joined: Thu Apr 01, 2010 10:24 am

by CarpetFibre

Well I found it on google street view: http://goo.gl/maps/6ttpj

It does look horrendously steep, That's all I can say.

Edit: this link to streetview shows how ridiculously steep that road is: http://goo.gl/maps/YD5LU

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djm
Posts: 1403
Joined: Thu May 14, 2009 12:19 pm
Location: Norway

by djm

CarpetFibre: Yeah.. Haha. That last link does serve some justice to the steepness :-) Add to it that the road on the left hand side is fairly steep aswell, probably 8-10%.

badlydubbed
Posts: 25
Joined: Wed Sep 19, 2012 6:46 pm

by badlydubbed

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makoy
Posts: 716
Joined: Sun Sep 05, 2010 11:33 am
Location: Subic Bay, Philippines

by makoy

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Esterhas
Posts: 33
Joined: Tue Mar 27, 2012 4:35 pm

by Esterhas

The Shuttle's swan song over JPL

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dolophonic
Posts: 871
Joined: Tue Mar 15, 2005 2:43 am
Location: The 'Dena

by dolophonic

@Esterhas.. very cool

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micky
Posts: 5765
Joined: Thu Sep 21, 2006 8:57 pm
Location: Vicenza
Contact:

by micky

Epic picture!

Zitter
Posts: 575
Joined: Fri Jun 03, 2011 9:12 pm
Location: Los Angeles, CA

by Zitter

@Esterhas my hometown and some of my favorite mountains to ride in

stiffee69er
Posts: 83
Joined: Thu Dec 31, 2009 9:27 am
Location: UK

by stiffee69er

Where's JPL? :noidea:

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Tinea Pedis
Posts: 8615
Joined: Sat Mar 14, 2009 6:08 am
Contact:

by Tinea Pedis

Guys, think we can help this poor chap out?

viewtopic.php?f=3&t=107438

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HammerTime2
Posts: 5813
Joined: Thu May 04, 2006 4:43 pm
Location: Wherever there's a mountain beckoning to be climbed

by HammerTime2

stiffee69er wrote:Where's JPL? :noidea:
Caltech's Jet Propulsion Laboratory in Pasadena, California (USA) , just Northeast of Los Angeles.
http://www.jpl.nasa.gov/news/news.php?release=2012-299
http://en.wikipedia.org/wiki/Jet_Propulsion_Laboratory
http://www.jpl.nasa.gov/news/

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stella-azzurra
Posts: 5066
Joined: Mon Jan 23, 2006 6:35 am
Location: New York

by stella-azzurra

djm wrote:HammerTime2: Yep.. I've climbed/dropped 30% grades on my MTB and I'd say this was worse.

The data from Strava perhaps isn't worth much, but shows there's a pretty steep section of road.
http://app.strava.com/rides/22587328#z8874|8920" onclick="window.open(this.href);return false;" onclick="window.open(this.href);return false;" onclick="window.open(this.href);return false;

I may be wrong.. maybe if somebody with less fatigue (I'm knackered :-) ) could calculate the real incline of the first section of this road using this map. The increase in elevation is 5 metres per line. Scale is also indicated at the bottom.

Link to map: http://kart.finn.no/?lng=10.69311&lat=59.83008&zoom=20&mapType=finnvector


I might have the wrong road here but MapMyRide shows elevation on mapped roads. You can give it a section of road and it will give you back elevation with gradient.

If you give it too long of a road it will average it out by the way.

But this road is short enough.

Fjordvangveien.JPG


This is how to calculate

Percent slope =

%m = (rise/run)*100

%m = (100ft./1320ft.)*100
%m = (.0757)*100
%m = 7.6 %
I never took drugs to improve my performance at any time. I will be willing to stick my finger into a polygraph test if anyone with big media pull wants to take issue. If you buy a signed poster now it will not be tarnished later. --Graeme Obree

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HammerTime2
Posts: 5813
Joined: Thu May 04, 2006 4:43 pm
Location: Wherever there's a mountain beckoning to be climbed

by HammerTime2

Let d be the distance along the road, and e be the elevation gain. Then the percent grade is 100*e/[square root of (d*d- e*e)] . Note that d is the hypotenuse of the right triangle with sides e and square root of(d*d - e*e). Note that in stella's formula above, e is the rise, but square root of (d*d- e*e), not d, is the run. The run is not shown on the map, and needs to be computed (as above or by mathematically equivalent procedure).

If you want to solve for the elevation gain needed for 40% grade over a given distance along the road, d, the answer is d*sin(arctan(.4)) . So for example, for a distance along the road of 500m, an elevation gain of 185.7m (185,7 european style) corresponds to a 40% grade. You can get the answer in google by doing a "search" on 500*sin(arctan(.4)) , even if you don't know anything about trigonometry. So you'd need to cross 37 contour lines of 5m elevation difference over the span of 500m distance along the road to correspond to 40% grade.

I'll leave it to someone else to identify a suitable section of the road and count the contour crossings and corresponding distance along the road on djm's map. Then plug into the formula in the first paragraph, and there's your answer (presuming the map, with its elevation contours, is accurate).

Please note that the approximation of percent grade being 100*e/d becomes more and more inaccurate as the grade increases (not bad for 6% grade, not good for 40% grade). Using this approximate method for an elevation gain of 185.7m over a distance along the road of 500m results in (an approximate) grade of 37.1%, as opposed to the actual grade of 40%.

by Weenie


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djm
Posts: 1403
Joined: Thu May 14, 2009 12:19 pm
Location: Norway

by djm

There's a reason I picked law over any field that involves anything more than basic maths.. :-)

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