numbers numbers numbers

[drjones96]

If you don't want to show your results then just say that.

wich i did in the first place

so why do not answer the question then ?
if it so simple for you ?

Man I just don't get you at all. You make some nice wheels but I just don't understand you.

[cees]

If you don't want to show your results then just say that.

wich i did in the first place

so why do not answer the question then ?
if it so simple for you ?

Man I just don't get you at all. You make some nice wheels but I just don't understand you.

and i do not understand you
i was asking a question
and you only can trough trash
why!!!!
why do you just simple answer the question
if you do not know
just do not repond this is not necesary
nobody learns from this

[kAb]

cees,

If i were currently deciding between ADA and LW, and was going to make a decision today. The remarks on the forum would be enough to get the LW. Quit it.

[Mottsauce]

When Amadeus said that you brought up the subject again I think he meant that you made a whole new thread (this one) on the same subject as the last one...kind of beating a dead horse

[drjones96]

people attacked me on not giving numbers of a test
i wonder how many people know what those numbers mean to them

if i say measured 1 gramm drag

how many can then say
what it means in watts at 50km/h

and what it mean with their own performance let say they need 400 watt
to ride 50 km/h ( if you have 1 gramm of drag)
how much would it infleunce their speed
flat road same air pressure same speed



test done at 50 km/h
at sea level
1220 pressure


i really wonder
cees

OK....what are your units on pressure?

Mil Standard Atmosphere
T = 288.16 K
P = 101325 N/m^2
density = 1.2250 kg/m^3

....working on this problem because you challenged me to do it.

[cees]

cees,

If i were currently deciding between ADA and LW, and was going to make a decision today. The remarks on the forum would be enough to get the LW. Quit it.

again i am not here to sell any wheels
i am busy enough

this has nothing to do with anyone
you making this like it i am not
i ask a question on something totaly differant

1 gram of drag
can also be on clothing or cables
has nothing to do with the products you mention
i do not know else how to ask this do you ??????

[cees]

OK....what are your units on pressure?

Mil Standard Atmosphere
T = 288.16 K
P = 101325 N/m^2
density = 1.2250 kg/m^3

....working on this problem because you challenged me to do it.

kg

[cees]

When Amadeus said that you brought up the subject again I think he meant that you made a whole new thread (this one) on the same subject as the last one...kind of beating a dead horse

sorry this is a totaly differant subject

[drjones96]

OK....what are your units on pressure?

Mil Standard Atmosphere
T = 288.16 K
P = 101325 N/m^2
density = 1.2250 kg/m^3

....working on this problem because you challenged me to do it.

kg

kg is mass....

[ergott]

I'm trying to help you out here. This forum is filled with people who are very analytical. They are not usually satisfied with statements that are not backed up with imperical evidence. This is moreso the case when someone makes a statement that might be contrary to more common ideas (right or wrong). When you post your findings, you are greated skeptically because you do not elaborate on your findings. There are enough people here that are intelligent enough to follow you when you get technical. They would appreciate you giving as much detail as possible. I'm sure you would if it weren't for restrictions put on you buy the purchaser of the data you have collected. It might be better to either leave out the vague posts all together or maybe explain with as much detail as you can without violating your aggreement. You should be able to post numbers if ou don't mention manufactureres. You could label the wheels A and B and describe them. Don't treat members like they would not understand you.

-Eric

[cees]

OK....what are your units on pressure?

Mil Standard Atmosphere
T = 288.16 K
P = 101325 N/m^2
density = 1.2250 kg/m^3

....working on this problem because you challenged me to do it.

kg

kg is mass....

that is true i reported the density
thats kg/m^3

so thats the local air pressure and not the dynamic one´s

[cees]

I'm trying to help you out here. This forum is filled with people who are very analytical. They are not usually satisfied with statements that are not backed up with imperical evidence. This is moreso the case when someone makes a statement that might be contrary to more common ideas (right or wrong). When you post your findings, you are greated skeptically because you do not elaborate on your findings. There are enough people here that are intelligent enough to follow you when you get technical. They would appreciate you giving as much detail as possible. I'm sure you would if it weren't for restrictions put on you buy the purchaser of the data you have collected. It might be better to either leave out the vague posts all together or maybe explain with as much detail as you can without violating your aggreement. You should be able to post numbers if ou don't mention manufactureres. You could label the wheels A and B and describe them. Don't treat members like they would not understand you.

-Eric

eric you know i respect you
i simple ask a question
did not treat any one
and release data from a wheel test was a totaly differant tread
this is totaly about something else
there are people who hear about let say suits that reduce drag and given by grams

my simply question was how many poeple know this nothing more or less
what others make out of it is beyound me
this tread is about 1 gram drag and what it means in performance!

[drjones96]

Your units are wacky. I (and most other aero engineers) measure drag in force units. g and kg are mass units. If you say you removed so many 'counts' of drag from a known model then you'd be talking about the drag coefficient. But you're not you're talking about delta grams. I'm trying to make sense of this but I'm not having much luck.

OK lets assume that:
When you say 1g you're refering to the mass term in force where F=M*a.

So 1N=1000 g*m/s^2.

So you'd be saying that -1g delta would mean a delta of 0.001N in Force.

I calculated that if the rider is inputting 400Watts @ 50km/h his propulsive force is 28.8N.

So if I reduced his required propulsive force by 0.001N to 28.799N that intern reduces his required input power by 0.014Watts to 399.986 Watts to maintain the same speed of 50km/h.

P = F * v

400W=1440 N*km/hr

1440 N*km/h = F * 50 km/h

F=28.8N

Delta Force = 0.001N

Fnew=28.799N

Pnew = Fnew * vo

Pnew = 28.799 * 50 = 1439.95 N*km/h = 399.986W

tiny

[Samu Ilonen]

This forum is filled with people who are very analytical. They are not usually satisfied with statements that are not backed up with imperical evidence. Eric

As I also sell bikes/sport things as I'm bike mechanic, I have found this to be bit problem. As I hear all day long lot of crap from those other sale boys that are not passinonated from cycling as I do...As it came in my mind to go and buy new digicamera...w/o searching tests all week etc....I run like problem when camera shop sale man claimed that: " This Sony is much better than this Canon..." From tech numbers, I coudn't see that. So I figured that Sony has better sale margin, not tech, and bought Canon. I speaking cheap pocket camera, Ixus 50, so it's anyway good for tech documentation on WW..W.

[RTW]

Where is this coming from? I don't get what sparked this thread.

ADA or LW based on no research into the differences. LWs. I know a shop 5 miles away that has a set of standards in stock. I have never seen an ADA.

That said Cees, it would be great if you could lift their profile a bit. Answer some questions on them.

I know Madcow has some, and LWs, I must get his input and preferences.